Per Genya's request I fitted vector asymmetry in each sector to the data
varying target angle. My fitting model is
A_{measured}(Q^2) = P0 \frac{A^{V}_{ed}}{1+P1*Q^4}. Here, P0 is a Pe*Pz
and P1 quantifies a contribution from background (asumming background is
constant). Here are my results:
right: left:
\theta = 45 \Chi^2 =
10.8/4 \Chi^2 = 5.48/4
P0 = 0.545 \pm
0.048 P0 = 0.494 \pm 0.03
P1 = 2.629 \pm
1.59 P1 = 3.953 \pm 1.3
\theta = 40 \Chi^2 =
11.36/4 \Chi^2 = 5.46/4
P0 = 0.431 \pm
0.04 P0 = 0.4634 \pm 0.03
P1 = 2.96 \pm 1.7
P1 = 3.787 \pm 1.3
\theta = 35 \Chi^2 =
11.83/4 \Chi^2 = 5.453/4
P0 = 0.45 \pm
0.038 P0 = 0.44 \pm 0.03
P1 = 3.2 \pm 1.78
P1 = 3.64 \pm 1.3
\theta = 30 \Chi^2 =
12.2/4 \Chi^2 = 5.48/4
P0 = 0.42 \pm 0.036
P0 = 0.422 \pm 0.025
P1 = 3.5 \pm 1.86
P1 = 3.6 \pm 1.2
\theta = 25 \Chi^2 =
12.6/4 \Chi^2 = 5.48/4
P0 = 0.399 \pm 0.035
P0 = 0.4075 \pm 0.024
P1 = 3.68 \pm 1.92
P1 = 3.395 \pm 1.3
Draw your own conclusions. Vitaliy
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